Two sources of equal emf are connected to an external resistance R. The internal resistances of the two sources are $${{R}_{1}}$$ and $${{R}_{2}}\,({{R}_{2}}{{R}_{1}})$$. If the potential difference across the source having internal resistance $${{R}_{2}}$$ is zero, then [AIEEE 2005]

Question

Two sources of equal emf are connected to an external resistance R. The internal resistances of the two sources are $${{R}_{1}}$$ and $${{R}_{2}}\,({{R}_{2}}>{{R}_{1}})$$. If the potential difference across the source having internal resistance $${{R}_{2}}$$ is zero, then [AIEEE 2005]

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$$R={{R}_{1}}{{R}_{2}}/({{R}_{1}}+{{R}_{2}})$$

TuteeHUB · Answer

$$R={{R}_{1}}{{R}_{2}}/({{R}_{2}}-{{R}_{1}})$$

TuteeHUB · Answer

$$R={{R}_{2}}\times ({{R}_{1}}+{{R}_{2}})/({{R}_{2}}-{{R}_{1}})$$

TuteeHUB · Answer

$$R={{R}_{2}}-{{R}_{1}}$$

1.	Two sources of equal emf are connected to an external resistance R. The internal resistances of the two sources are \[{{R}_{1}}\] and \[{{R}_{2}}\,({{R}_{2}}>{{R}_{1}})\]. If the potential difference across the source having internal resistance \[{{R}_{2}}\] is zero, then [AIEEE 2005]
A.	\[R={{R}_{1}}{{R}_{2}}/({{R}_{1}}+{{R}_{2}})\]
B.	\[R={{R}_{1}}{{R}_{2}}/({{R}_{2}}-{{R}_{1}})\]
C.	\[R={{R}_{2}}\times ({{R}_{1}}+{{R}_{2}})/({{R}_{2}}-{{R}_{1}})\]
D.	\[R={{R}_{2}}-{{R}_{1}}\]
Answer» E.

Two sources of equal emf are connected to an external resistance R. The internal resistances of the two sources are \[{{R}_{1}}\] and \[{{R}_{2}}\,({{R}_{2}}>{{R}_{1}})\]. If the potential difference across the source having internal resistance \[{{R}_{2}}\] is zero, then [AIEEE 2005]

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