Two rings each of radius 'a' are coaxial and the distance between their centres is a. The masses of the rings are$${{M}_{1}}\text{ }and\text{ }{{M}_{2}}$$. The work done in transporting a particle of a small mass m from centre $${{\operatorname{C}}_{1}} to {{C}_{2}}$$is :

Question

TuteeHUB · Accepted Answer

$$\frac{Gm\left( {{M}_{2}}-{{M}_{1}} \right)}{\sqrt{2}}a$$

TuteeHUB · Answer

$$\frac{Gm\left( {{M}_{2}}-{{M}_{1}} \right)}{a}$$

TuteeHUB · Answer

$$\frac{Gm\left( {{M}_{2}}-{{M}_{1}} \right)}{a\sqrt{2}}\left( \sqrt{2}+1 \right)$$

TuteeHUB · Answer

$$\frac{Gm\left( {{M}_{2}}-{{M}_{1}} \right)}{a\sqrt{2}}\left( \sqrt{2}-1 \right)$$

1.	Two rings each of radius 'a' are coaxial and the distance between their centres is a. The masses of the rings are\[{{M}_{1}}\text{ }and\text{ }{{M}_{2}}\]. The work done in transporting a particle of a small mass m from centre \[{{\operatorname{C}}_{1}} to {{C}_{2}}\]is :
A.	\[\frac{Gm\left( {{M}_{2}}-{{M}_{1}} \right)}{a}\]
B.	\[\frac{Gm\left( {{M}_{2}}-{{M}_{1}} \right)}{a\sqrt{2}}\left( \sqrt{2}+1 \right)\]
C.	\[\frac{Gm\left( {{M}_{2}}-{{M}_{1}} \right)}{a\sqrt{2}}\left( \sqrt{2}-1 \right)\]
D.	\[\frac{Gm\left( {{M}_{2}}-{{M}_{1}} \right)}{\sqrt{2}}a\]
Answer» D. \[\frac{Gm\left( {{M}_{2}}-{{M}_{1}} \right)}{\sqrt{2}}a\]

Two rings each of radius 'a' are coaxial and the distance between their centres is a. The masses of the rings are\[{{M}_{1}}\text{ }and\text{ }{{M}_{2}}\]. The work done in transporting a particle of a small mass m from centre \[{{\operatorname{C}}_{1}} to {{C}_{2}}\]is :

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