MCQOPTIONS
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| 1. |
Two particles of masses \[{{m}_{1}}\] and \[{{m}_{2}}\] in projectile motion have velocities \[{{\vec{v}}_{1}}\] and \[{{\vec{v}}_{2}}\] respectively at time t = 0. They collide at time \[{{t}_{0}}\]. Their velocities become \[{{\vec{v}}_{1}}'\] and \[{{\vec{v}}_{2}}'\] at time \[2{{t}_{0}}\] while still moving in air. The value of \[|({{m}_{1}}\overrightarrow{{{v}_{1}}}'\,+{{m}_{2}}\overrightarrow{{{v}_{2}}}')-({{m}_{1}}\overrightarrow{{{v}_{1}}}\,+{{m}_{2}}\overrightarrow{{{v}_{2}}})\]| is [IIT-JEE Screening 2001] |
| A. | Zero |
| B. | \[({{m}_{1}}+{{m}_{2}})g{{t}_{0}}\] |
| C. | \[2({{m}_{1}}+{{m}_{2}})g{{t}_{0}}\] |
| D. | \[\frac{1}{2}({{m}_{1}}+{{m}_{2}})g{{t}_{0}}\] |
| Answer» D. \[\frac{1}{2}({{m}_{1}}+{{m}_{2}})g{{t}_{0}}\] | |