Two identical photo-cathodes receive light of frequencies $${{f}_{1}}$$ and $${{f}_{2}}$$. If the velocities of the photo electrons (of mass $$m$$) coming out are respectively $${{v}_{1}}$$ and $${{v}_{2}}$$, then [AIEEE 2003]

Question

Two identical photo-cathodes receive light of frequencies $${{f}_{1}}$$ and $${{f}_{2}}$$. If the velocities of the photo electrons (of mass $$m$$) coming out are respectively $${{v}_{1}}$$ and $${{v}_{2}}$$, then            [AIEEE 2003]

TuteeHUB · Accepted Answer

$${{v}_{1}}+{{v}_{2}}={{\left[ \frac{2h}{m}\left( {{f}_{1}}+{{f}_{2}} \right) \right]}^{1/2}}$$

TuteeHUB · Answer

$${{v}_{1}}-{{v}_{2}}={{\left[ \frac{2h}{m}\left( {{f}_{1}}-{{f}_{2}} \right) \right]}^{1/2}}$$

TuteeHUB · Answer

$$v_{1}^{2}-v_{2}^{2}=\frac{2h}{m}\left( {{f}_{1}}-{{f}_{2}} \right)$$

TuteeHUB · Answer

$$v_{1}^{2}+v_{2}^{2}=\frac{2h}{m}\left( {{f}_{1}}+{{f}_{2}} \right)$$

1.	Two identical photo-cathodes receive light of frequencies \[{{f}_{1}}\] and \[{{f}_{2}}\]. If the velocities of the photo electrons (of mass \[m\]) coming out are respectively \[{{v}_{1}}\] and \[{{v}_{2}}\], then [AIEEE 2003]
A.	\[{{v}_{1}}-{{v}_{2}}={{\left[ \frac{2h}{m}\left( {{f}_{1}}-{{f}_{2}} \right) \right]}^{1/2}}\]
B.	\[v_{1}^{2}-v_{2}^{2}=\frac{2h}{m}\left( {{f}_{1}}-{{f}_{2}} \right)\]
C.	\[{{v}_{1}}+{{v}_{2}}={{\left[ \frac{2h}{m}\left( {{f}_{1}}+{{f}_{2}} \right) \right]}^{1/2}}\]
D.	\[v_{1}^{2}+v_{2}^{2}=\frac{2h}{m}\left( {{f}_{1}}+{{f}_{2}} \right)\]
Answer» C. \[{{v}_{1}}+{{v}_{2}}={{\left[ \frac{2h}{m}\left( {{f}_{1}}+{{f}_{2}} \right) \right]}^{1/2}}\]

Two identical photo-cathodes receive light of frequencies \[{{f}_{1}}\] and \[{{f}_{2}}\]. If the velocities of the photo electrons (of mass \[m\]) coming out are respectively \[{{v}_{1}}\] and \[{{v}_{2}}\], then [AIEEE 2003]

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