Two identical capacitors, have the same capacitance C. One of them is charged to potential $${{V}_{1}}$$ and the other to $${{V}_{2}}$$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is [IIT-JEE (Screening) 2002]

Question

Two identical capacitors, have the same capacitance C. One of them is charged to potential $${{V}_{1}}$$ and the other to $${{V}_{2}}$$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is                   [IIT-JEE (Screening) 2002]

TuteeHUB · Accepted Answer

$$\frac{1}{4}C{{\left( {{V}_{1}}+{{V}_{2}} \right)}^{2}}$$

TuteeHUB · Answer

$$\frac{1}{4}C(V_{1}^{2}-V_{2}^{2})$$

TuteeHUB · Answer

$$\frac{1}{4}C(V_{1}^{2}+V_{2}^{2})$$

TuteeHUB · Answer

$$\frac{1}{4}C{{\left( {{V}_{1}}-{{V}_{2}} \right)}^{2}}$$

1.	Two identical capacitors, have the same capacitance C. One of them is charged to potential \[{{V}_{1}}\] and the other to \[{{V}_{2}}\]. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is [IIT-JEE (Screening) 2002]
A.	\[\frac{1}{4}C(V_{1}^{2}-V_{2}^{2})\]
B.	\[\frac{1}{4}C(V_{1}^{2}+V_{2}^{2})\]
C.	\[\frac{1}{4}C{{\left( {{V}_{1}}-{{V}_{2}} \right)}^{2}}\]
D.	\[\frac{1}{4}C{{\left( {{V}_{1}}+{{V}_{2}} \right)}^{2}}\]
Answer» D. \[\frac{1}{4}C{{\left( {{V}_{1}}+{{V}_{2}} \right)}^{2}}\]

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