Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongations is 0.5 cm, the elongation ($$l$$) of each wireis$${{Y}_{s}}(steel)=2.0\times {{10}^{11}}N/{{m}^{2}}$$ $${{Y}_{c}}(copper)=1.2\times {{10}^{11}}N/{{m}^{2}}$$

Question

TuteeHUB · Accepted Answer

$${{l}_{s}}=1.25\,cm,\,{{l}_{c}}=0.75\,cm$$

TuteeHUB · Answer

$${{l}_{s}}=0.75\,cm,\,{{l}_{c}}=1.25\,cm$$

TuteeHUB · Answer

$${{l}_{s}}=0.25\,cm,\,{{l}_{c}}=0.75\,cm$$

TuteeHUB · Answer

$${{l}_{s}}=0.75\,cm,\,{{l}_{c}}=0.25\,cm$$

1.	Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongations is 0.5 cm, the elongation (\[l\]) of each wireis\[{{Y}_{s}}(steel)=2.0\times {{10}^{11}}N/{{m}^{2}}\] \[{{Y}_{c}}(copper)=1.2\times {{10}^{11}}N/{{m}^{2}}\]
A.	\[{{l}_{s}}=0.75\,cm,\,{{l}_{c}}=1.25\,cm\]
B.	\[{{l}_{s}}=1.25\,cm,\,{{l}_{c}}=0.75\,cm\]
C.	\[{{l}_{s}}=0.25\,cm,\,{{l}_{c}}=0.75\,cm\]
D.	\[{{l}_{s}}=0.75\,cm,\,{{l}_{c}}=0.25\,cm\]
Answer» B. \[{{l}_{s}}=1.25\,cm,\,{{l}_{c}}=0.75\,cm\]

Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongations is 0.5 cm, the elongation (\[l\]) of each wireis\[{{Y}_{s}}(steel)=2.0\times {{10}^{11}}N/{{m}^{2}}\] \[{{Y}_{c}}(copper)=1.2\times {{10}^{11}}N/{{m}^{2}}\]

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