MCQOPTIONS
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| 1. |
Two equal charges \[q\] of opposite sign separated by a distance \[2a\] constitute an electric dipole of dipole moment \[p\]. If \[P\] is a point at a distance \[r\] from the centre of the dipole and the line joining the centre of the dipole to this point makes an angle \[\theta \] with the axis of the dipole, then the potential at \[P\] is given by \[(r>>2a)\] (Where\[p=2qa\]) [MP PET 1997] |
| A. | \[V=\frac{p\cos \theta }{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\] |
| B. | \[V=\frac{p\cos \theta }{4\pi {{\varepsilon }_{0}}r}\] |
| C. | \[V=\frac{p\sin \theta }{4\pi {{\varepsilon }_{0}}r}\] |
| D. | \[V=\frac{p\cos \theta }{2\pi {{\varepsilon }_{0}}{{r}^{2}}}\] |
| Answer» B. \[V=\frac{p\cos \theta }{4\pi {{\varepsilon }_{0}}r}\] | |