Two dielectric slabs of constant $${{K}_{1}}$$ and $${{K}_{2}}$$ have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor [MNR 1985; MP PET 1999; DCE 2002]

Question

Two dielectric slabs of constant $${{K}_{1}}$$ and $${{K}_{2}}$$ have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor                                                        [MNR 1985; MP PET 1999; DCE 2002]

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$$\frac{2{{\varepsilon }_{0}}A}{2}({{K}_{1}}+{{K}_{2}})$$

TuteeHUB · Answer

$$\frac{2{{\varepsilon }_{0}}A}{2}\left( \frac{{{K}_{1}}+{{K}_{2}}}{{{K}_{1}}\times {{K}_{2}}} \right)$$

TuteeHUB · Answer

$$\frac{2{{\varepsilon }_{0}}A}{2}\left( \frac{{{K}_{1}}\times {{K}_{2}}}{{{K}_{1}}+{{K}_{2}}} \right)$$

TuteeHUB · Answer

$$\frac{2{{\varepsilon }_{0}}A}{d}\left( \frac{{{K}_{1}}\times {{K}_{2}}}{{{K}_{1}}+{{K}_{2}}} \right)$$

1.	Two dielectric slabs of constant \[{{K}_{1}}\] and \[{{K}_{2}}\] have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor [MNR 1985; MP PET 1999; DCE 2002]
A.	\[\frac{2{{\varepsilon }_{0}}A}{2}({{K}_{1}}+{{K}_{2}})\]
B.	\[\frac{2{{\varepsilon }_{0}}A}{2}\left( \frac{{{K}_{1}}+{{K}_{2}}}{{{K}_{1}}\times {{K}_{2}}} \right)\]
C.	\[\frac{2{{\varepsilon }_{0}}A}{2}\left( \frac{{{K}_{1}}\times {{K}_{2}}}{{{K}_{1}}+{{K}_{2}}} \right)\]
D.	\[\frac{2{{\varepsilon }_{0}}A}{d}\left( \frac{{{K}_{1}}\times {{K}_{2}}}{{{K}_{1}}+{{K}_{2}}} \right)\]
Answer» E.

Two dielectric slabs of constant \[{{K}_{1}}\] and \[{{K}_{2}}\] have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor [MNR 1985; MP PET 1999; DCE 2002]

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