_ Two bodies of masses m‚Äö√á√Ö and m‚Äö√á√á are hung from the ends of a rope, passing over a frictionless pulley as shown in the figure below. The acceleration of the string will be Engineering Mechanics$?

Question

TuteeHUB · Accepted Answer

2g (m‚Äö√á√Ö - m‚Äö√á√á)/(m‚Äö√á√Ö + m‚Äö√á√á)

TuteeHUB · Answer

g (m‚Äö√á√Ö - m‚Äö√á√á)/(m‚Äö√á√Ö + m‚Äö√á√á)

TuteeHUB · Answer

g (m‚Äö√á√Ö + m‚Äö√á√á)/(m‚Äö√á√Ö - m‚Äö√á√á)

TuteeHUB · Answer

2g (m‚Äö√á√Ö + m‚Äö√á√á)/(m‚Äö√á√Ö - m‚Äö√á√á)

1.	_ Two bodies of masses m‚Äö√á√Ö and m‚Äö√á√á are hung from the ends of a rope, passing over a frictionless pulley as shown in the figure below. The acceleration of the string will be Engineering Mechanics$?
A.	g (m‚Äö√á√Ö - m‚Äö√á√á)/(m‚Äö√á√Ö + m‚Äö√á√á)
B.	2g (m‚Äö√á√Ö - m‚Äö√á√á)/(m‚Äö√á√Ö + m‚Äö√á√á)
C.	g (m‚Äö√á√Ö + m‚Äö√á√á)/(m‚Äö√á√Ö - m‚Äö√á√á)
D.	2g (m‚Äö√á√Ö + m‚Äö√á√á)/(m‚Äö√á√Ö - m‚Äö√á√á)
Answer» B. 2g (m‚Äö√á√Ö - m‚Äö√á√á)/(m‚Äö√á√Ö + m‚Äö√á√á)

_ Two bodies of masses m‚Äö√á√Ö and m‚Äö√á√á are hung from the ends of a rope, passing over a frictionless pulley as shown in the figure below. The acceleration of the string will be Engineering Mechanics$?

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