Three charges \[{{q}_{1}},\text{ }+{{q}_{2}}\] and \[{{q}_{3}}\]are place as shown in the figure. The x-component of the force on\[-{{q}_{1}}\]is proportional to

\[\frac{{{q}_{2}}}{{{b}^{2}}}+\frac{{{q}_{3}}}{{{a}^{2}}}\cos \theta \]

\[\frac{{{q}_{2}}}{{{b}^{2}}}-\frac{{{q}_{3}}}{{{a}^{2}}}\cos \theta \]

\[\frac{{{q}_{2}}}{{{b}^{2}}}+\frac{{{q}_{3}}}{{{a}^{2}}}\sin \theta \]

\[\frac{{{q}_{2}}}{{{b}^{2}}}-\frac{{{q}_{3}}}{{{a}^{2}}}\sin \theta \]

Three charges \[{{q}_{1}},\text{ }+{{q}_{2}}\] and \[{{q}_{3}}\]are pl

1.	Three charges \[{{q}_{1}},\text{ }+{{q}_{2}}\] and \[{{q}_{3}}\]are place as shown in the figure. The x-component of the force on\[-{{q}_{1}}\]is proportional to
A.	\[\frac{{{q}_{2}}}{{{b}^{2}}}-\frac{{{q}_{3}}}{{{a}^{2}}}\cos \theta \]
B.	\[\frac{{{q}_{2}}}{{{b}^{2}}}+\frac{{{q}_{3}}}{{{a}^{2}}}\sin \theta \]
C.	\[\frac{{{q}_{2}}}{{{b}^{2}}}+\frac{{{q}_{3}}}{{{a}^{2}}}\cos \theta \]
D.	\[\frac{{{q}_{2}}}{{{b}^{2}}}-\frac{{{q}_{3}}}{{{a}^{2}}}\sin \theta \]
Answer» C. \[\frac{{{q}_{2}}}{{{b}^{2}}}+\frac{{{q}_{3}}}{{{a}^{2}}}\cos \theta \]