MCQOPTIONS
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MCQOPTIONS
| 1. |
The YDSE apparatus is as shown in Fig. The condition for point P to be a dark fringe is |
| A. | \[({{l}_{1}}-{{l}_{3}})+({{l}_{2}}-{{l}_{4}})=n\lambda \] |
| B. | \[({{l}_{1}}-{{l}_{2}})+({{l}_{3}}-{{l}_{4}})=\frac{(2n-1)}{2}\lambda \] |
| C. | \[({{l}_{1}}-{{l}_{3}})+({{l}_{2}}-{{l}_{4}})=\frac{(2n-1)\lambda }{2}\] |
| D. | \[({{l}_{1}}-{{l}_{2}})+({{l}_{4}}-{{l}_{3}})=\frac{(2n-1)\lambda }{2}\] |
| Answer» C. \[({{l}_{1}}-{{l}_{3}})+({{l}_{2}}-{{l}_{4}})=\frac{(2n-1)\lambda }{2}\] | |