The weighted mean of first n natural numbers whose weights are equal to the squares of corresponding numbers is [Pb. CET 1989]

The weighted mean of first n natural numbers whose weights are equal t

1.	The weighted mean of first n natural numbers whose weights are equal to the squares of corresponding numbers is [Pb. CET 1989]
A.	\[\frac{n+1}{2}\]
B.	\[\frac{3n(n+1)}{2(2n+1)}\]
C.	\[\frac{(n+1)(2n+1)}{6}\]
D.	\[\frac{n(n+1)}{2}\]
Answer» C. \[\frac{(n+1)(2n+1)}{6}\]

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The weighted mean of first n natural numbers whose weights are equal to the squares of corresponding numbers is [Pb. CET 1989]

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