The volume of a sphere is 38808 cu. cm. The curved surface area of

1.	The volume of a sphere is 38808 cu. cm. The curved surface area of the sphere is ?
A.	5544 sq. cm
B.	1386 sq. cm
C.	8316 sq. cm
D.	4158 sq. cm
Answer» B. 1386 sq. cm

Discussion

No Comment Found

Related MCQs

In Mass Haul diagram (Mass diagram), the term haul represents the
In the planimeter formula for measuring area, A = M (FR – IR ± 10 N) + C, the additive constant is considered when
Determine the approximate quantity of earthwork for a road in embankment having a length of 120 m on a uniform level ground. The width of formation is 10 m and side slopes are 3 ∶ 1. The heights of the bank at the ends are 1 m and 1.5 m, respectively. Use trapezoidal method considering average of areas at the two ends.
If the cross sectional areas of an embankment at 60 m intervals are 20, 40, 60, 50 and 30 sq.m, then the volume (cum) of the embankment on the basis of prismoidal rule is
If the surface of the earth is rough, then the exact amount of earthwork can be found:
Find the amount of earthwork from the mid-sectional area method, assuming there is no transverse slope, while the elevations at both the ends of the land with the same slope are 1 m and 1.6 m respectively, the width and length of the road is 10 m and 200 m respectively and the side slope is 2: 1.
A cross-section area of river flow can be calculated by using following formula ______.
In a cross staff survey, the perpendicular offsets are taken on right and left of the chain line AD as shown in figure – all values are in ‘metres’. The area enclosed by ABCDEFA, computed by trapezoidal method is
A road embankment 10 m wide at the formation level with side slopes 2:1 and with an average height of 5 m is constructed with an average gradient of 1:40 from the contour 220 m to 280 m. Find the volume of earthwork.
How much is the measuring capability of digital planimeter w.r.t. an ordinary planimeter?

The volume of a sphere is 38808 cu. cm. The curved surface area of the sphere is ?

Discussion

No Comment Found

Related MCQs

Reply to Comment