The vertices of a hyperbola are at (0, 0) and (10, 0) and one of its foci is at (18, 0). The equation of the hyperbola is

\[\frac{{{x}^{2}}}{25}-\frac{{{(y-5)}^{2}}}{144}=1\]

\[\frac{{{x}^{2}}}{25}-\frac{{{y}^{2}}}{144}=1\]

\[\frac{{{(x-5)}^{2}}}{25}-\frac{{{y}^{2}}}{144}=1\]

\[\frac{{{(x-5)}^{2}}}{25}-\frac{{{(y-5)}^{2}}}{144}=1\]

The vertices of a hyperbola are at (0, 0) and (10, 0) and one of its f

1.	The vertices of a hyperbola are at (0, 0) and (10, 0) and one of its foci is at (18, 0). The equation of the hyperbola is
A.	\[\frac{{{x}^{2}}}{25}-\frac{{{y}^{2}}}{144}=1\]
B.	\[\frac{{{(x-5)}^{2}}}{25}-\frac{{{y}^{2}}}{144}=1\]
C.	\[\frac{{{x}^{2}}}{25}-\frac{{{(y-5)}^{2}}}{144}=1\]
D.	\[\frac{{{(x-5)}^{2}}}{25}-\frac{{{(y-5)}^{2}}}{144}=1\]
Answer» C. \[\frac{{{x}^{2}}}{25}-\frac{{{(y-5)}^{2}}}{144}=1\]

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The vertices of a hyperbola are at (0, 0) and (10, 0) and one of its foci is at (18, 0). The equation of the hyperbola is

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