The value of \[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( \frac{3x-4}{3x+2} \right)}^{\frac{x+1}{3}}}\] is equal to [Pb. CET 2004]

The value of \[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( \frac

1.	The value of \[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( \frac{3x-4}{3x+2} \right)}^{\frac{x+1}{3}}}\] is equal to [Pb. CET 2004]
A.	\[{{e}^{-1/3}}\]
B.	\[{{e}^{-2/3}}\]
C.	\[{{e}^{-1}}\]
D.	\[{{e}^{-2}}\]
Answer» C. \[{{e}^{-1}}\]

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The value of \[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( \frac{3x-4}{3x+2} \right)}^{\frac{x+1}{3}}}\] is equal to [Pb. CET 2004]

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