The value of \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{({{2}^{{{x}^{n}}}}){{e}^{\frac{1}{^{x}}}}-({{3}^{{{x}^{n}}}}){{e}^{\frac{1}{x}}}}{{{x}^{n}}}\](where \[n\in N\]) is

\[n\log n\left( \frac{2}{3} \right)\]

\[\log n\left( \frac{2}{3} \right)\]

The value of \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{({{2}^{{

1.	The value of \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{({{2}^{{{x}^{n}}}}){{e}^{\frac{1}{^{x}}}}-({{3}^{{{x}^{n}}}}){{e}^{\frac{1}{x}}}}{{{x}^{n}}}\](where \[n\in N\]) is
A.	\[\log n\left( \frac{2}{3} \right)\]
B.	0
C.	\[n\log n\left( \frac{2}{3} \right)\]
D.	Not defined
Answer» C. \[n\log n\left( \frac{2}{3} \right)\]

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The value of \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{({{2}^{{{x}^{n}}}}){{e}^{\frac{1}{^{x}}}}-({{3}^{{{x}^{n}}}}){{e}^{\frac{1}{x}}}}{{{x}^{n}}}\](where \[n\in N\]) is

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