The value of \[\underset{n\to \infty }{\mathop{\lim }}\,\frac{1+2+3+....n}{{{n}^{2}}+100}\]is equal [Pb. CET 2002]

The value of \[\underset{n\to \infty }{\mathop{\lim }}\,\frac{1+2+3+..

1.	The value of \[\underset{n\to \infty }{\mathop{\lim }}\,\frac{1+2+3+....n}{{{n}^{2}}+100}\]is equal [Pb. CET 2002]
A.	\[\infty \]
B.	\[\frac{1}{2}\]
C.	2
D.	0
Answer» C. 2

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The value of \[\underset{n\to \infty }{\mathop{\lim }}\,\frac{1+2+3+....n}{{{n}^{2}}+100}\]is equal [Pb. CET 2002]

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