The value of the expression\[1-\frac{{{\sin }^{2}}y}{1+\cos \,y}+\frac{1+\cos \,y}{\sin \,y}-\frac{\sin \,\,y}{1-\cos \,y}\]is equal to

The value of the expression\[1-\frac{{{\sin }^{2}}y}{1+\cos \,y}+\frac

1.	The value of the expression\[1-\frac{{{\sin }^{2}}y}{1+\cos \,y}+\frac{1+\cos \,y}{\sin \,y}-\frac{\sin \,\,y}{1-\cos \,y}\]is equal to
A.	0
B.	1
C.	\[\sin \,y\]
D.	\[\cos \,y\]
Answer» E.

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The value of the expression\[1-\frac{{{\sin }^{2}}y}{1+\cos \,y}+\frac{1+\cos \,y}{\sin \,y}-\frac{\sin \,\,y}{1-\cos \,y}\]is equal to

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