The value of the definite integral \[\int_{0}^{1}{\frac{dx}{{{x}^{2}}+2x\cos \alpha +1}}\] for \[0

\[{{\tan }^{-1}}(\sin \alpha )\]

\[\frac{\alpha }{2}{{(\sin \alpha )}^{-1}}\]

The value of the definite integral \[\int_{0}^{1}{\frac{dx}{{{x}^{2}}+

1.	The value of the definite integral \[\int_{0}^{1}{\frac{dx}{{{x}^{2}}+2x\cos \alpha +1}}\] for \[0
A.	\[\sin \alpha \]
B.	\[{{\tan }^{-1}}(\sin \alpha )\]
C.	\[\alpha \sin \alpha \]
D.	\[\frac{\alpha }{2}{{(\sin \alpha )}^{-1}}\]
Answer» E.

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The value of the definite integral \[\int_{0}^{1}{\frac{dx}{{{x}^{2}}+2x\cos \alpha +1}}\] for \[0

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