The value of n in the following equation is Cr2O2-7 + 14H+ + ne 2 Cr3

1.	The value of n in the following equation is Cr₂O^2-₇ + 14H⁺ + ne 2 Cr³⁺ + 7H₂O⁺
A.	6
B.	2
C.	3
D.	4
Answer» B. 2

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Match List-I (Oxidation number) with List-II (The element) ad select the correct answer using the code given below the list : <table width="100%"><tr><td></td><td>List-I (Oxidation number)</td><td></td><td>List-II(The element)</td></tr><tr><td>F.</td><td>2</td><td>1.</td><td>Oxidation number of Mn in MnO2</td></tr><tr><td>G.</td><td>3</td><td>2.</td><td>Oxidation number of S in H2S2O7</td></tr><tr><td>H.</td><td>4</td><td>3.</td><td>Oxidation number of Ca in CaO</td></tr><tr><td>J.</td><td>6</td><td>4.</td><td>Oxidation number of Al in NaAIH4</td></tr></table>Codes :<table width="40%"><tr><td></td><td>F</td><td>G</td><td>H</td><td>J</td></tr><tr><td>A.</td><td>3</td><td>4</td><td>1</td><td>2</td></tr><tr><td>B.</td><td>4</td><td>3</td><td>1</td><td>2</td></tr><tr><td>C.</td><td>3</td><td>4</td><td>2</td><td>1</td></tr><tr><td>D.</td><td>4</td><td>3</td><td>2</td><td>1</td></tr></table>
Oxidation state of Mn in acidic KMnO4 change from is :

The value of n in the following equation is Cr2O2-7 + 14H+ + ne 2 Cr3+ + 7H2O+

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The value of n in the following equation is Cr₂O^2-₇ + 14H⁺ + ne 2 Cr³⁺ + 7H₂O⁺