1.

The value of m, for which the line \[y=mx+\frac{25\sqrt{3}}{3}\], is a normal  to the conic \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1\], is [MP PET 2004]

A.            \[\sqrt{3}\]                               
B.            \[-\frac{2}{\sqrt{3}}\]
C.            \[-\frac{\sqrt{3}}{2}\]               
D.            1
Answer» C.            \[-\frac{\sqrt{3}}{2}\]               


Discussion

No Comment Found

Related MCQs