MCQOPTIONS
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| 1. |
The value of m, for which the line \[y=mx+\frac{25\sqrt{3}}{3}\], is a normal to the conic \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1\], is [MP PET 2004] |
| A. | \[\sqrt{3}\] |
| B. | \[-\frac{2}{\sqrt{3}}\] |
| C. | \[-\frac{\sqrt{3}}{2}\] |
| D. | 1 |
| Answer» C. \[-\frac{\sqrt{3}}{2}\] | |