The value of \[\int\limits_{0}^{1}{\frac{dx}{{{e}^{x}}+e}}\] is equal to

\[\log \left( \frac{1+e}{2} \right)\]

\[\frac{1}{e}\log \left( \frac{1+e}{2} \right)\]

\[\log \left( \frac{2}{1+e} \right)\]

The value of \[\int\limits_{0}^{1}{\frac{dx}{{{e}^{x}}+e}}\] is equal

1.	The value of \[\int\limits_{0}^{1}{\frac{dx}{{{e}^{x}}+e}}\] is equal to
A.	\[\frac{1}{e}\log \left( \frac{1+e}{2} \right)\]
B.	\[\log \left( \frac{1+e}{2} \right)\]
C.	\[\frac{1}{e}\log (1+e)\]
D.	\[\log \left( \frac{2}{1+e} \right)\]
Answer» B. \[\log \left( \frac{1+e}{2} \right)\]

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The value of \[\int\limits_{0}^{1}{\frac{dx}{{{e}^{x}}+e}}\] is equal to

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