The value of \[\int{\frac{\log x}{{{(x+1)}^{2}}}dx}\] is [UPSEAT 1999]

\[\frac{\log x}{\left( x+1 \right)}+\log x-\log \,(x+1)\]

\[\frac{-\log x}{x+1}+\log x-\log \,(x+1)\]

\[\frac{\log x}{x+1}-\log x-\log \,(x+1)\]

\[\frac{-\log x}{x+1}-\log x-\log \,(x+1)\]

The value of \[\int{\frac{\log x}{{{(x+1)}^{2}}}dx}\] is [UP

1.	The value of \[\int{\frac{\log x}{{{(x+1)}^{2}}}dx}\] is [UPSEAT 1999]
A.	\[\frac{-\log x}{x+1}+\log x-\log \,(x+1)\]
B.	\[\frac{\log x}{\left( x+1 \right)}+\log x-\log \,(x+1)\]
C.	\[\frac{\log x}{x+1}-\log x-\log \,(x+1)\]
D.	\[\frac{-\log x}{x+1}-\log x-\log \,(x+1)\]
Answer» B. \[\frac{\log x}{\left( x+1 \right)}+\log x-\log \,(x+1)\]

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The value of \[\int{\frac{\log x}{{{(x+1)}^{2}}}dx}\] is [UPSEAT 1999]

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