The value of \[\int{\frac{dx}{3-2x-{{x}^{2}}}}\] will be [UPSEAT 1999]

\[\frac{1}{3}\log \,\left( \frac{3+x}{1-x} \right)\]

\[\frac{1}{4}\log \,\left( \frac{3+x}{1-x} \right)\]

\[\frac{1}{2}\log \,\left( \frac{3+x}{1-x} \right)\]

\[\log \,\left( \frac{1-x}{3+x} \right)\]

The value of \[\int{\frac{dx}{3-2x-{{x}^{2}}}}\] will be

1.	The value of \[\int{\frac{dx}{3-2x-{{x}^{2}}}}\] will be [UPSEAT 1999]
A.	\[\frac{1}{4}\log \,\left( \frac{3+x}{1-x} \right)\]
B.	\[\frac{1}{3}\log \,\left( \frac{3+x}{1-x} \right)\]
C.	\[\frac{1}{2}\log \,\left( \frac{3+x}{1-x} \right)\]
D.	\[\log \,\left( \frac{1-x}{3+x} \right)\]
Answer» B. \[\frac{1}{3}\log \,\left( \frac{3+x}{1-x} \right)\]

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The value of \[\int{\frac{dx}{3-2x-{{x}^{2}}}}\] will be [UPSEAT 1999]

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