The value of \[\int_{0}^{1}{\frac{dx}{{{e}^{x}}+{{e}^{-x}}}}\] is [SCRA 1980]

\[{{\tan }^{-1}}\left( \frac{1-e}{1+e} \right)\]

\[{{\tan }^{-1}}\left( \frac{e-1}{e+1} \right)\]

\[{{\tan }^{-1}}e+\frac{\pi }{4}\]

The value of \[\int_{0}^{1}{\frac{dx}{{{e}^{x}}+{{e}^{-x}}}}\] is �

1.	The value of \[\int_{0}^{1}{\frac{dx}{{{e}^{x}}+{{e}^{-x}}}}\] is [SCRA 1980]
A.	\[{{\tan }^{-1}}\left( \frac{1-e}{1+e} \right)\]
B.	\[{{\tan }^{-1}}\left( \frac{e-1}{e+1} \right)\]
C.	\[\frac{\pi }{4}\]
D.	\[{{\tan }^{-1}}e+\frac{\pi }{4}\]
Answer» C. \[\frac{\pi }{4}\]

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The value of \[\int_{0}^{1}{\frac{dx}{{{e}^{x}}+{{e}^{-x}}}}\] is [SCRA 1980]

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