The value of \[\frac{^{n}{{C}_{0}}}{n}+\frac{^{n}{{C}_{1}}}{n+1}+\frac{^{n}{{C}_{2}}}{n+2}+...+\frac{^{n}{{C}_{n}}}{2n}\]is equal to

\[\int\limits_{0}^{1}{{{x}^{n-1}}{{(1+x)}^{n}}dx}\]

\[\int\limits_{0}^{1}{{{x}^{n-1}}{{(1-x)}^{n}}dx}\]

\[\int\limits_{0}^{1}{{{x}^{n}}{{(x-1)}^{n-1}}dx}\]

\[\int\limits_{0}^{1}{{{(1-x)}^{n}}{{x}^{n-1}}dx}\]

The value of \[\frac{^{n}{{C}_{0}}}{n}+\frac{^{n}{{C}_{1}}}{n+1}+\frac

1.	The value of \[\frac{^{n}{{C}_{0}}}{n}+\frac{^{n}{{C}_{1}}}{n+1}+\frac{^{n}{{C}_{2}}}{n+2}+...+\frac{^{n}{{C}_{n}}}{2n}\]is equal to
A.	\[\int\limits_{0}^{1}{{{x}^{n-1}}{{(1-x)}^{n}}dx}\]
B.	\[\int\limits_{0}^{1}{{{x}^{n}}{{(x-1)}^{n-1}}dx}\]
C.	\[\int\limits_{0}^{1}{{{x}^{n-1}}{{(1+x)}^{n}}dx}\]
D.	\[\int\limits_{0}^{1}{{{(1-x)}^{n}}{{x}^{n-1}}dx}\]
Answer» C. \[\int\limits_{0}^{1}{{{x}^{n-1}}{{(1+x)}^{n}}dx}\]

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The value of \[\frac{^{n}{{C}_{0}}}{n}+\frac{^{n}{{C}_{1}}}{n+1}+\frac{^{n}{{C}_{2}}}{n+2}+...+\frac{^{n}{{C}_{n}}}{2n}\]is equal to

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