The value of a (a > 0) for which the area bounded by the curves \[y=\frac{x}{6}+\frac{1}{{{x}^{2}}},y=0,x=a\] and \[x=2a\]has the least value is

The value of a (a > 0) for which the area bounded by the curves \[y=

1.	The value of a (a > 0) for which the area bounded by the curves \[y=\frac{x}{6}+\frac{1}{{{x}^{2}}},y=0,x=a\] and \[x=2a\]has the least value is
A.	2
B.	(b \[\sqrt{2}\]
C.	\[{{2}^{1/3}}\]
D.	1
Answer» E.

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The value of a (a > 0) for which the area bounded by the curves \[y=\frac{x}{6}+\frac{1}{{{x}^{2}}},y=0,x=a\] and \[x=2a\]has the least value is

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