The two capacitors, shown in the circuit, are initially uncharged and the cell is ideal. The switch S is closed at t=0. Which of the following functions represents the current i(t) through the cell as a function of time? Here$${{i}_{0}},\,{{i}_{1}},\,{{i}_{2}}$$are constants.

Question

TuteeHUB · Accepted Answer

$$i(t)={{i}_{1}}+{{i}_{1}}{{e}^{-t/\tau }}$$; $$\tau =3C\times \frac{R}{3}$$

TuteeHUB · Answer

$$i(t)={{i}_{0}}+{{i}_{1}}{{e}^{-t/\tau }}$$; $$\tau =3C\times \frac{R}{3}$$

TuteeHUB · Answer

$$i(t)={{i}_{0}}+{{i}_{1}}{{e}^{-t/\tau }}+{{i}_{2}}{{e}^{-t/2\tau }}$$;  $$\tau =RC$$

TuteeHUB · Answer

$$i(t)={{i}_{0}}+{{i}_{1}}{{e}^{-t/\tau }}$$;  $$\tau =3RC$$

1.	The two capacitors, shown in the circuit, are initially uncharged and the cell is ideal. The switch S is closed at t=0. Which of the following functions represents the current i(t) through the cell as a function of time? Here\[{{i}_{0}},\,{{i}_{1}},\,{{i}_{2}}\]are constants.
A.	\[i(t)={{i}_{0}}+{{i}_{1}}{{e}^{-t/\tau }}\]; \[\tau =3C\times \frac{R}{3}\]
B.	\[i(t)={{i}_{0}}+{{i}_{1}}{{e}^{-t/\tau }}+{{i}_{2}}{{e}^{-t/2\tau }}\]; \[\tau =RC\]
C.	\[i(t)={{i}_{1}}+{{i}_{1}}{{e}^{-t/\tau }}\]; \[\tau =3C\times \frac{R}{3}\]
D.	\[i(t)={{i}_{0}}+{{i}_{1}}{{e}^{-t/\tau }}\]; \[\tau =3RC\]
Answer» C. \[i(t)={{i}_{1}}+{{i}_{1}}{{e}^{-t/\tau }}\]; \[\tau =3C\times \frac{R}{3}\]

The two capacitors, shown in the circuit, are initially uncharged and the cell is ideal. The switch S is closed at t=0. Which of the following functions represents the current i(t) through the cell as a function of time? Here\[{{i}_{0}},\,{{i}_{1}},\,{{i}_{2}}\]are constants.

Discussion

No Comment Found

Related MCQs

Reply to Comment