MCQOPTIONS
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| 1. |
The tuning circuit of a radio receiver has a resistance of \[50\,\Omega \], an inductor of 10 mH and a variable capacitor. A 1 MHz radio wave produces a potential difference of 0.1 mV. The values of the capacitor to produce resonance is \[(Take\,{{\pi }^{2}}=10)\] |
| A. | 2.5 pF |
| B. | 5.0 pF |
| C. | 25 pF |
| D. | 50 pF |
| Answer» B. 5.0 pF | |