The total vapor pressure of a mixture of 1 mol of volatile component A (\[P_{A}^{O}\]= 100 mm Hg) and 3 mol of volatile component B (\[P_{B}^{O}\]=80 mm Hg) is 90 mm Hg. For such case:

there is a positive deviation from Raoult's law

force of attraction between A and B is smaller than that between A and A or between B and B

all the above statements are correct

The total vapor pressure of a mixture of 1 mol of volatile component A

1.	The total vapor pressure of a mixture of 1 mol of volatile component A (\[P_{A}^{O}\]= 100 mm Hg) and 3 mol of volatile component B (\[P_{B}^{O}\]=80 mm Hg) is 90 mm Hg. For such case:
A.	there is a positive deviation from Raoult's law
B.	boiling point has been lowered
C.	force of attraction between A and B is smaller than that between A and A or between B and B
D.	all the above statements are correct
Answer» E.

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The total vapor pressure of a mixture of 1 mol of volatile component A (\[P_{A}^{O}\]= 100 mm Hg) and 3 mol of volatile component B (\[P_{B}^{O}\]=80 mm Hg) is 90 mm Hg. For such case:

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