

MCQOPTIONS
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1. |
The total number of protons in 10 g of calcium carbonate is (\[{{N}_{0}}=6.023\times {{10}^{23}}\]) |
A. | \[1.5057\times {{10}^{24}}\] |
B. | \[2.0478\times {{10}^{24}}\] |
C. | \[3.0115\times {{10}^{24}}\] |
D. | \[4.0956\times {{10}^{24}}\] |
Answer» D. \[4.0956\times {{10}^{24}}\] | |