MCQOPTIONS
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| 1. |
The time period of a simple pendulum measured inside a stationary lift is found to be T. If the lift starts accelerating upwards with an acceleration g/3, the time period is [EAMCET 1994; CMEET Bihar 1995; RPMT 2000] |
| A. | \[T\sqrt{3}\] |
| B. | \[T\sqrt{3}/2\] |
| C. | \[T/\sqrt{3}\] |
| D. | \[T/3\] |
| Answer» C. \[T/\sqrt{3}\] | |