The symmetric equation of lines \[3x+2y+z-5=0\] and \[x+y-2z-3=0\], is

1.	The symmetric equation of lines \[3x+2y+z-5=0\] and \[x+y-2z-3=0\], is
A.	\[\frac{x-1}{5}=\frac{y-4}{7}=\frac{z-0}{1}\]
B.	\[\frac{x+1}{5}=\frac{y+4}{7}=\frac{z-0}{1}\]
C.	\[\frac{x+1}{-5}=\frac{y-4}{7}=\frac{z-0}{1}\]
D.	\[\frac{x-1}{-5}=\frac{y-4}{7}=\frac{z-0}{1}\]
Answer» D. \[\frac{x-1}{-5}=\frac{y-4}{7}=\frac{z-0}{1}\]

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The symmetric equation of lines \[3x+2y+z-5=0\] and \[x+y-2z-3=0\], is

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