The sum of the series \[1.3.5+.2.5.8+3.7.11+.........\]upto \['n'\] terms is [Dhanbad Engg. 1972]

\[\frac{n\,(n-1)(9{{n}^{2}}+23n+12)}{6}\]

\[\frac{n\,(n+1)(9{{n}^{2}}+23n+13)}{6}\]

\[\frac{(n+1)(9{{n}^{2}}+23n+13)}{6}\]

\[\frac{n\,(9{{n}^{2}}+23n+13)}{6}\]

The sum of the series \[1.3.5+.2.5.8+3.7.11+.........\]upto \['n'\] te

1.	The sum of the series \[1.3.5+.2.5.8+3.7.11+.........\]upto \['n'\] terms is [Dhanbad Engg. 1972]
A.	\[\frac{n\,(n+1)(9{{n}^{2}}+23n+13)}{6}\]
B.	\[\frac{n\,(n-1)(9{{n}^{2}}+23n+12)}{6}\]
C.	\[\frac{(n+1)(9{{n}^{2}}+23n+13)}{6}\]
D.	\[\frac{n\,(9{{n}^{2}}+23n+13)}{6}\]
Answer» B. \[\frac{n\,(n-1)(9{{n}^{2}}+23n+12)}{6}\]

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The sum of the series \[1.3.5+.2.5.8+3.7.11+.........\]upto \['n'\] terms is [Dhanbad Engg. 1972]

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