The sum of the series \[1.2.3+2.3.4+3.4.5+.......\] to n terms is [Kurukshetra CEE 1998]

\[\frac{1}{4}n(n+1)(n+2)(n+3)\]

The sum of the series \[1.2.3+2.3.4+3.4.5+.......\] to n terms is [Kur

1.	The sum of the series \[1.2.3+2.3.4+3.4.5+.......\] to n terms is [Kurukshetra CEE 1998]
A.	\[n(n+1)(n+2)\]
B.	\[(n+1)(n+2)(n+3)\]
C.	\[\frac{1}{4}n(n+1)(n+2)(n+3)\]
D.	\[\frac{1}{4}(n+1)(n+2)(n+3)\]
Answer» D. \[\frac{1}{4}(n+1)(n+2)(n+3)\]

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The sum of the series \[1.2.3+2.3.4+3.4.5+.......\] to n terms is [Kurukshetra CEE 1998]

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