The sum of \[(n-1)\] terms of \[1+(1+3)+\] \[(1+3+5)+.......\] is [RPET 1999]

The sum of \[(n-1)\] terms of \[1+(1+3)+\] \[(1+3+5)+.......\] is [R

1.	The sum of \[(n-1)\] terms of \[1+(1+3)+\] \[(1+3+5)+.......\] is [RPET 1999]
A.	\[\frac{n\,(n+1)\,(2n+1)}{6}\]
B.	\[\frac{{{n}^{2}}(n+1)}{4}\]
C.	\[\frac{n\,(n-1)\,(2n-1)}{6}\]
D.	\[{{n}^{2}}\]
Answer» D. \[{{n}^{2}}\]

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The sum of \[(n-1)\] terms of \[1+(1+3)+\] \[(1+3+5)+.......\] is [RPET 1999]

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