1.

The sum of first \[n\] terms of the given series \[{{1}^{2}}+{{2.2}^{2}}+{{3}^{2}}+{{2.4}^{2}}+{{5}^{2}}+{{2.6}^{2}}+............\]is\[\frac{n{{(n+1)}^{2}}}{2}\], when \[n\] is even. When \[n\] is odd, the sum will be [IIT 1988]

A. \[\frac{n{{(n+1)}^{2}}}{2}\]
B. \[\frac{1}{2}{{n}^{2}}(n+1)\]
C. \[n{{(n+1)}^{2}}\]
D. None of these
Answer» C. \[n{{(n+1)}^{2}}\]


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