The solution of \[(x\sqrt{1+{{y}^{2}}})dx+(y\sqrt{1+{{x}^{2}}})dy=0\] is

\[\sqrt{1+{{x}^{2}}}-\sqrt{1+{{y}^{2}}}=c\]

\[\sqrt{1+{{x}^{2}}}+\sqrt{1+{{y}^{2}}}=c\]

\[\sqrt{1+{{x}^{2}}}-\sqrt{1+{{y}^{2}}}=c\]

\[{{(1+{{x}^{2}})}^{3/2}}+{{(1+{{y}^{2}})}^{3/2}}=c\]

The solution of \[(x\sqrt{1+{{y}^{2}}})dx+(y\sqrt{1+{{x}^{2}}})dy=0\]

1.	The solution of \[(x\sqrt{1+{{y}^{2}}})dx+(y\sqrt{1+{{x}^{2}}})dy=0\] is
A.	\[\sqrt{1+{{x}^{2}}}+\sqrt{1+{{y}^{2}}}=c\]
B.	\[\sqrt{1+{{x}^{2}}}-\sqrt{1+{{y}^{2}}}=c\]
C.	\[{{(1+{{x}^{2}})}^{3/2}}+{{(1+{{y}^{2}})}^{3/2}}=c\]
D.	None of these
Answer» B. \[\sqrt{1+{{x}^{2}}}-\sqrt{1+{{y}^{2}}}=c\]

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The solution of \[(x\sqrt{1+{{y}^{2}}})dx+(y\sqrt{1+{{x}^{2}}})dy=0\] is

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