The solution of the equation\[x\int\limits_{0}^{x}{y(t)dt=(x+1)\int_{0}^{x}{ty(t)dt,x>0}}\] is

\[y=\frac{c}{{{x}^{3}}}{{e}^{{{x}^{3}}}}\]

\[y=c{{x}^{3}}{{e}^{-{{x}^{3}}}}\]

\[\frac{c}{{{x}^{3}}}{{e}^{-x}}\]

The solution of the equation\[x\int\limits_{0}^{x}{y(t)dt=(x+1)\int_{0

1.	The solution of the equation\[x\int\limits_{0}^{x}{y(t)dt=(x+1)\int_{0}^{x}{ty(t)dt,x>0}}\] is
A.	\[y=\frac{c}{{{x}^{3}}}{{e}^{{{x}^{3}}}}\]
B.	\[y=c{{x}^{3}}{{e}^{-{{x}^{3}}}}\]
C.	\[\frac{c}{{{x}^{3}}}{{e}^{-x}}\]
D.	None of these
Answer» E.

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The solution of the equation\[x\int\limits_{0}^{x}{y(t)dt=(x+1)\int_{0}^{x}{ty(t)dt,x>0}}\] is

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