The solution of the equation \[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{e}^{-2x}}\] is [AIEEE 2002]

\[\frac{1}{4}{{e}^{-2x}}+c{{x}^{2}}+d\]

\[\frac{1}{4}{{e}^{-2x}}+cx+d\]

\[\frac{1}{4}{{e}^{-2x}}+c{{x}^{2}}+d\]

The solution of the equation \[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{e}^{-2x

1.	The solution of the equation \[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{e}^{-2x}}\] is [AIEEE 2002]
A.	\[\frac{1}{4}{{e}^{-2x}}\]
B.	\[\frac{1}{4}{{e}^{-2x}}+cx+d\]
C.	\[\frac{1}{4}{{e}^{-2x}}+c{{x}^{2}}+d\]
D.	\[\frac{1}{4}{{e}^{-2x}}+c+d\]
Answer» C. \[\frac{1}{4}{{e}^{-2x}}+c{{x}^{2}}+d\]

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The solution of the equation \[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{e}^{-2x}}\] is [AIEEE 2002]

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