The solution of the equation \[\frac{dy}{dx}=\sqrt{\frac{1-{{y}^{2}}}{1-{{x}^{2}}}}\] is

\[{{\sin }^{-1}}y{{\sin }^{-1}}x=c\]

\[{{\sin }^{-1}}y-{{\sin }^{-1}}x=c\]

The solution of the equation \[\frac{dy}{dx}=\sqrt{\frac{1-{{y}^{2}}}{

1.	The solution of the equation \[\frac{dy}{dx}=\sqrt{\frac{1-{{y}^{2}}}{1-{{x}^{2}}}}\] is
A.	\[{{\sin }^{-1}}y-{{\sin }^{-1}}x=c\]
B.	\[{{\sin }^{-1}}y{{\sin }^{-1}}x=c\]
C.	\[{{\sin }^{-1}}(xy)=2\]
D.	None of these
Answer» B. \[{{\sin }^{-1}}y{{\sin }^{-1}}x=c\]

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The solution of the equation \[\frac{dy}{dx}=\sqrt{\frac{1-{{y}^{2}}}{1-{{x}^{2}}}}\] is

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