The solution of the equation \[\frac{dy}{dx}=\frac{y}{x}\left( \log \frac{y}{x}+1 \right)\] is

\[\log \left( \frac{y}{x} \right)=cx\]

The solution of the equation \[\frac{dy}{dx}=\frac{y}{x}\left( \log \f

1.	The solution of the equation \[\frac{dy}{dx}=\frac{y}{x}\left( \log \frac{y}{x}+1 \right)\] is
A.	\[\log \left( \frac{y}{x} \right)=cx\]
B.	\[\frac{y}{x}=\log y+c\]
C.	\[y=\log y+1\]
D.	\[y=xy+c\]
Answer» B. \[\frac{y}{x}=\log y+c\]

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The solution of the equation \[\frac{dy}{dx}=\frac{y}{x}\left( \log \frac{y}{x}+1 \right)\] is

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