The solution of the differential equation \[x({{e}^{2y}}-1)dy+({{x}^{2}}-1){{e}^{y}}dx=0\]is [AISSE 1990]

\[{{e}^{y}}-{{e}^{-y}}=\log x-\frac{{{x}^{2}}}{2}+c\]\[\]

\[{{e}^{y}}+{{e}^{-y}}=\log x-\frac{{{x}^{2}}}{2}+c\]

\[{{e}^{y}}-{{e}^{-y}}=\log x-\frac{{{x}^{2}}}{2}+c\]\[\]

\[{{e}^{y}}+{{e}^{-y}}=\log x+\frac{{{x}^{2}}}{2}+c\]

The solution of the differential equation \[x({{e}^{2y}}-1)dy+({{x}^{2

1.	The solution of the differential equation \[x({{e}^{2y}}-1)dy+({{x}^{2}}-1){{e}^{y}}dx=0\]is [AISSE 1990]
A.	\[{{e}^{y}}+{{e}^{-y}}=\log x-\frac{{{x}^{2}}}{2}+c\]
B.	\[{{e}^{y}}-{{e}^{-y}}=\log x-\frac{{{x}^{2}}}{2}+c\]\[\]
C.	\[{{e}^{y}}+{{e}^{-y}}=\log x+\frac{{{x}^{2}}}{2}+c\]
D.	None of these
Answer» B. \[{{e}^{y}}-{{e}^{-y}}=\log x-\frac{{{x}^{2}}}{2}+c\]\[\]

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The solution of the differential equation \[x({{e}^{2y}}-1)dy+({{x}^{2}}-1){{e}^{y}}dx=0\]is [AISSE 1990]

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