MCQOPTIONS
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| 1. |
The solution of the differential equation \[({{x}^{2}}+{{y}^{2}})dx=2xydy\] is [MP PET 2003; Orissa JEE 2005] |
| A. | \[x=c({{x}^{2}}+{{y}^{2}})\] |
| B. | \[x=c({{x}^{2}}-{{y}^{2}})\] |
| C. | \[x+c({{x}^{2}}-{{y}^{2}})=0\] |
| D. | None of these |
| Answer» C. \[x+c({{x}^{2}}-{{y}^{2}})=0\] | |