The solution of the differential equation \[{{x}^{2}}\frac{dy}{dx}={{x

1.	The solution of the differential equation \[{{x}^{2}}\frac{dy}{dx}={{x}^{2}}+xy+{{y}^{2}}\] is
A.	\[{{\tan }^{-1}}\left( \frac{y}{x} \right)=\log x+c\]
B.	\[{{\tan }^{-1}}\left( \frac{y}{x} \right)=-\log x+c\]
C.	\[{{\sin }^{-1}}\left( \frac{y}{x} \right)=\log x+c\]
D.	\[{{\tan }^{-1}}\left( \frac{x}{y} \right)=\log x+c\]
Answer» B. \[{{\tan }^{-1}}\left( \frac{y}{x} \right)=-\log x+c\]

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The solution of the differential equation \[{{x}^{2}}\frac{dy}{dx}={{x}^{2}}+xy+{{y}^{2}}\] is

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