The solution of the differential equation \[\frac{dy}{dx}+\frac{1+{{x}

1.	The solution of the differential equation \[\frac{dy}{dx}+\frac{1+{{x}^{2}}}{x}=0\] is
A.	\[y=-\frac{1}{2}{{\tan }^{-1}}x+c\]
B.	\[y+\log x+\frac{{{x}^{2}}}{2}+c=0\]
C.	\[y=\frac{1}{2}{{\tan }^{-1}}x+c\]
D.	\[y-\log x-\frac{{{x}^{2}}}{2}=c\]
Answer» C. \[y=\frac{1}{2}{{\tan }^{-1}}x+c\]

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The solution of the differential equation \[\frac{dy}{dx}+\frac{1+{{x}^{2}}}{x}=0\] is

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