The solution of the differential equation \[\frac{dy}{dx}=\frac{3{{x}^{2}}{{y}^{4}}+2xy}{{{x}^{2}}-2{{x}^{3}}{{y}^{3}}}\] is

\[\frac{{{x}^{2}}}{3y}-{{x}^{3}}{{y}^{2}}=c\]

\[\frac{{{y}^{2}}}{x}-{{x}^{3}}{{y}^{2}}=c\]

\[\frac{{{x}^{2}}}{{{y}^{2}}}+{{x}^{3}}{{y}^{3}}=c\]

\[\frac{{{x}^{2}}}{y}+{{x}^{3}}{{y}^{2}}=c\]

The solution of the differential equation \[\frac{dy}{dx}=\frac{3{{

1.	The solution of the differential equation \[\frac{dy}{dx}=\frac{3{{x}^{2}}{{y}^{4}}+2xy}{{{x}^{2}}-2{{x}^{3}}{{y}^{3}}}\] is
A.	\[\frac{{{y}^{2}}}{x}-{{x}^{3}}{{y}^{2}}=c\]
B.	\[\frac{{{x}^{2}}}{{{y}^{2}}}+{{x}^{3}}{{y}^{3}}=c\]
C.	\[\frac{{{x}^{2}}}{y}+{{x}^{3}}{{y}^{2}}=c\]
D.	\[\frac{{{x}^{2}}}{3y}-{{x}^{3}}{{y}^{2}}=c\]
Answer» D. \[\frac{{{x}^{2}}}{3y}-{{x}^{3}}{{y}^{2}}=c\]

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The solution of the differential equation \[\frac{dy}{dx}=\frac{3{{x}^{2}}{{y}^{4}}+2xy}{{{x}^{2}}-2{{x}^{3}}{{y}^{3}}}\] is

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