1.

The solution of the differential equation \[\frac{dy}{dx}+\frac{3{{x}^{2}}}{1+{{x}^{3}}}y=\frac{{{\sin }^{2}}x}{1+{{x}^{3}}}\] is

A.                 \[y(1+{{x}^{3}})=x+\frac{1}{2}\sin 2x+c\]
B.                 \[y(1+{{x}^{3}})=cx+\frac{1}{2}\sin 2x\]
C.                 \[y(1+{{x}^{3}})=cx-\frac{1}{2}\sin 2x\]
D.                 \[y(1+{{x}^{3}})=\frac{x}{2}-\frac{1}{4}\sin 2x+c\]
Answer» E.


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