The solution of the differential equation \[\frac{dy}{dx}+2y\cot x=3{{x}^{2}}\text{cose}{{\text{c}}^{2}}x\]is

\[y{{\sin }^{2}}x={{x}^{3}}+c\]

The solution of the differential equation \[\frac{dy}{dx}+2y\cot x=3{{

1.	The solution of the differential equation \[\frac{dy}{dx}+2y\cot x=3{{x}^{2}}\text{cose}{{\text{c}}^{2}}x\]is
A.	\[y{{\sin }^{2}}x={{x}^{3}}+c\]
B.	\[y\sin x=c\]
C.	\[y\cos {{x}^{2}}=c\]
D.	\[y\sin {{x}^{2}}=c\]
Answer» B. \[y\sin x=c\]

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The solution of the differential equation \[\frac{dy}{dx}+2y\cot x=3{{x}^{2}}\text{cose}{{\text{c}}^{2}}x\]is

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