The solution of the differential equation \[{{\cos }^{2}}x\frac{{{d}^{2}}y}{d{{x}^{2}}}=1\] is

\[y=\log \sec x-{{c}_{1}}x+{{c}_{2}}\]

\[y=\log \sec x+{{c}_{1}}x+{{c}_{2}}\]

The solution of the differential equation \[{{\cos }^{2}}x\frac{{{d}^{

1.	The solution of the differential equation \[{{\cos }^{2}}x\frac{{{d}^{2}}y}{d{{x}^{2}}}=1\] is
A.	\[y=\log \cos x+cx\]
B.	\[y=\log \sec x+{{c}_{1}}x+{{c}_{2}}\]
C.	\[y=\log \sec x-{{c}_{1}}x+{{c}_{2}}\]
D.	None of these
Answer» C. \[y=\log \sec x-{{c}_{1}}x+{{c}_{2}}\]

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The solution of the differential equation \[{{\cos }^{2}}x\frac{{{d}^{2}}y}{d{{x}^{2}}}=1\] is

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